T31 = ([sigma]1 - [sigma]2 + [sigma]2 - [sigma]3)^2 T0

= T12 + T23 + 2([sigma]1 - [sigma]2)([sigma]2 - [sigma]3) T0;

so that T31 necessarily exceeds the sum of the other two interfacial

tensions. We are thus led to the important conclusion that according to

this hypothesis Neumann's triangle is necessarily imaginary, that one of

three fluids will always spread upon the interface of the other two.

Another point of importance may be easily illustrated by this theory,

viz. the dependency of capillarity upon abruptness of transition. "The

reason why the capillary force should disappear when the transition

between two liquids is sufficiently gradual will now be evident. Suppose

that the transition from 0 to [sigma] is made in two equal steps, the

thickness of the intermediate layer of density 1/2[sigma] being large

compared to the range of the molecular forces, but small in comparison

with the radius of curvature. At each step the difference of capillary

pressure is only one-quarter of that due to the sudden transition from 0

to [sigma], and thus altogether half the effect is lost by the

interposition of the layer. If there were three equal steps, the effect

would be reduced to one-third, and so on. When the number of steps is

infinite, the capillary pressure disappears altogether." ("Laplace's

Theory of Capillarity," Rayleigh, _Phil. Mag._, 1883, p. 315.)

According to Laplace's hypothesis the whole energy of any number of

contiguous strata of liquids is least when they are arranged in order of

density, so that this is the disposition favoured by the attractive

forces. The problem is to make the sum of the interfacial tensions a

minimum, each tension being proportional to the square of the difference

of densities of the two contiguous liquids in question. If the order of

stratification differ from that of densities, we can show that each step

of approximation to this order lowers the sum of tensions. To this end

consider the effect of the abolition of a stratum [sigma]_(n+1),

contiguous to [sigma]_n and [sigma]_(n+2). Before the change we have

([sigma]_n - [sigma](n+1))^2 + ([sigma]_(n+1) - [sigma]_(n+2))^2, and

afterwards ([sigma]_n - [sigma]_(n+2))^2. The second _minus_ the first,

or the increase in the sum of tensions, is thus

2([sigma]_n - [sigma]_(n+1))([sigma]_(n+1) - [sigma]_(n+2)).

Hence, if [sigma]_(n+1) be intermediate in magnitude between [sigma]_n

and [sigma]_(n+2), the sum of tensions is increased by the abolition of

the stratum; but, if [sigma]_(n+1) be not intermediate, the sum is

decreased. We see, then, that the removal of a stratum from between

neighbours where it is out of order and its introduction between

neighbours where it will be in order is doubly favourable to the

reduction of the sum of tensions; and since by a succession of such

steps we may arrive at the order of magnitude throughout, we conclude

that this is the disposition of minimum tensions and energy.

So far the results of Laplace's hypothesis are in marked accordance with

experiment; but if we follow it out further, discordances begin to

manifest themselves. According to (52)

____ ____ ____

\/ T31 = \/ T12 + \/ T23, (53)

a relation not verified by experiment. What is more, (52) shows that

according to the hypothesis T12 is necessarily positive; so that, if

the preceding argument be correct, no such thing as mixture of two

liquids could ever take place.

There are two apparent exceptions to Marangoni's rule which call for a

word of explanation. According to the rule, water, which has the lower

surface-tension, should spread upon the surface of mercury; whereas the

universal experience of the laboratory is that drops of water standing

upon mercury retain their compact form without the least tendency to

spread. To Quincke belongs the credit of dissipating the apparent

exception. He found that mercury specially prepared behaves quite

differently from ordinary mercury, and that a drop of water deposited

thereon spreads over the entire surface. The ordinary behaviour is

evidently the result of a film of grease, which adheres with great

obstinacy.

The process described by Quincke is somewhat elaborate; but there is

little difficulty in repeating the experiment if the mistake be avoided

of using a free surface already contaminated, as almost inevitably

happens when the mercury is poured from an ordinary bottle. The mercury

should be drawn from underneath, for which purpose an arrangement

similar to a chemical wash bottle is suitable, and it may be poured into

watch-glasses, previously dipped into strong sulphuric acid, rinsed in

distilled water, and dried over a Bunsen flame. When the glasses are

cool, they may be charged with mercury, of which the first part is

rejected. Operating in this way there is no difficulty in obtaining

surfaces upon which a drop of water spreads, although from causes that

cannot always be traced, a certain proportion of failures is met with.

As might be expected, the grease which produces these effects is largely

volatile. In many cases a very moderate preliminary warming of the

watch-glasses makes all the difference in the behaviour of the drop.

The behaviour of a drop of carbon bisulphide placed upon clean water is

also, at first sight, an exception to Marangoni's rule. So far from

spreading over the surface, as according to its lower surface-tension it

ought to do, it remains suspended in the form of a lens. Any dust that

may be lying upon the surface is not driven away to the edge of the

drop, as would happen in the case of oil. A simple modification of the

experiment suffices, however, to clear up the difficulty. If after the

deposition of the drop, a little lycopodium be scattered over the

surface, it is seen that a circular space surrounding the drop, of about

the size of a shilling, remains bare, and this, however often the

dusting be repeated, so long as any of the carbon bisulphide remains.

The interpretation can hardly be doubtful. The carbon bisulphide is

really spreading all the while, but on account of its volatility is

unable to reach any considerable distance. Immediately surrounding the

drop there is a film moving outwards at a high speed, and this carries

away almost instantaneously any dust that may fall upon it. The

phenomenon above described requires that the water-surface be clean. If

a very little grease be present, there is no outward flow and dust

remains undisturbed in the immediate neighbourhood of the drop.]

[Illustration: FIG. 6.]

_On the Rise of a Liquid in a Tube_.--Let a tube (fig. 6) whose internal

radius is r, made of a solid substance c, be dipped into a liquid a. Let

us suppose that the angle of contact for this liquid with the solid c is

an acute angle. This implies that the tension of the free surface of the

solid c is greater than that of the surface of contact of the solid with

the liquid a. Now consider the tension of the free surface of the liquid

a. All round its edge there is a tension T acting at an angle a with the

vertical. The circumference of the edge is 2[pi]r, so that the resultant

of this tension is a force 2[pi]rT cos[alpha] acting vertically upwards

on the liquid. Hence the liquid will rise in the tube till the weight

of the vertical column between the free surface and the level of the

liquid in the vessel balances the resultant of the surface-tension. The

upper surface of this column is not level, so that the height of the

column cannot be directly measured, but let us assume that h is the mean

height of the column, that is to say, the height of a column of equal

weight, but with a flat top. Then if r is the radius of the tube at the

top of the column, the volume of the suspended column is [pi]r^2h, and

its weight is [pi][rho]gr^2h, when [rho] is its density and g the

intensity of gravity. Equating this force with the resultant of the

tension

[pi][rho]gr^2h = 2[pi]rT cos[alpha],

or

h = 2T cos ([alpha]/[rho]gr).

Hence the mean height to which the fluid rises is inversely as the

radius of the tube. For water in a clean glass tube the angle of contact

is zero, and

h = 2T/[rho]gr.

For mercury in a glass tube the angle of contact is 128 deg. 52', the

cosine of which is negative. Hence when a glass tube is dipped into a

vessel of mercury, the mercury within the tube stands at a lower level

than outside it.

_Rise of a Liquid between Two Plates_.--When two parallel plates are

placed vertically in a liquid the liquid rises between them. If we now

suppose fig. 6 to represent a vertical section perpendicular to the

plates, we may calculate the rise of the liquid. Let l be the breadth of

the plates measured perpendicularly to the plane of the paper, then the

length of the line which bounds the wet and the dry parts of the plates

inside is l for each surface, and on this the tension T acts at an angle

[alpha] to the vertical. Hence the resultant of the surface-tension is

2lT cos[alpha]. If the distance between the inner surfaces of the plates

is a, and if the mean height of the film of fluid which rises between

them is h, the weight of fluid raised is [rho]ghla. Equating the

forces--

[rho]ghla = 2lT cos[alpha],

whence

h = 2T cos ([alpha]/[rho]ga).

This expression is the same as that for the rise of a liquid in a tube,

except that instead of r, the radius of the tube, we have a the distance

of the plates.

_Form of the Capillary Surface_.--The form of the surface of a liquid

acted on by gravity is easily determined if we assume that near the part

considered the line of contact of the surface of the liquid with that of

the solid bounding it is straight and horizontal, as it is when the

solids which constrain the liquid are bounded by surfaces formed by

horizontal and parallel generating lines. This will be the case, for

instance, near a flat plate dipped into the liquid. If we suppose these

generating lines to be normal to the plane of the paper, then all

sections of the solids parallel to this plane will be equal and similar

to each other, and the section of the surface of the liquid will be of

the same form for all such sections.

[Illustration: FIG. 7.]

Let us consider the portion of the liquid between two parallel sections

distant one unit of length. Let P1, P2 (fig. 7) be two points of the

surface; [theta]1, [theta]2 the inclination of the surface to the

horizon at P1 and P2; y1, y2 the heights of P1 and P2 above the level of

the liquid at a distance from all solid bodies. The pressure at any

point of the liquid which is above this level is negative unless another

fluid as, for instance, the air, presses on the upper surface, but it is

only the difference of pressures with which we have to do, because two

equal pressures on opposite sides of the surface produce no effect.

Encyclopaedia Britannica, 11th Edition, "Capefigue" to "Carneades" Volume 5, Slice 3 · 第 32 / 74 题