Differentiating with respect to c, we find

d[sigma] de

-------- = [rho], -- = [rho]([chi]' - 4[pi][rho][theta](0)) + 4[pi][rho]^2[theta](c).

dc dc

Hence the surface-tension

_

de / / c \

T = e - [sigma] -------- = 4[pi][rho]^2 ( | [theta](z)dz - c[theta](c) ).

d[sigma] \ _/0 /

Integrating the first term within brackets by parts, it becomes

_

/ c d[theta]

c[theta](c) - 0[theta](0) - | z -------- dz.

_/0 dz

Encyclopaedia Britannica, 11th Edition, "Capefigue" to "Carneades" Volume 5, Slice 3 · 第 18 / 74 题