CHAPTER XIII

REVERSIBLE REACTIONS AND CHEMICAL EQUILIBRIUM

~Reversible reactions.~ The reactions so far considered have been

represented as continuing, when once started, until one or the other

substance taking part in the reaction has been used up. In some

reactions this is not the case. For example, we have seen that when

steam is passed over hot iron the reaction is represented by the

equation

3Fe + 4H_{2}O = Fe_{3}O_{4} + 8H.

On the other hand, when hydrogen is passed over hot iron oxide the

reverse reaction takes place:

Fe_{3}O_{4} +8H = 3Fe + 4H_{2}O.

The reaction can therefore go in either direction, depending upon the

conditions of the experiment. Such a reaction is called a _reversible

reaction_. It is represented by an equation with double arrows in place

of the equality sign, thus:

3Fe + 4H_{2}O <--> Fe_{3}O_{4} + 8H.

In a similar way, the equation

N + 3H <--> NH_{3}

expresses the fact that under some conditions nitrogen may unite with

hydrogen to form ammonia, while under other conditions ammonia

decomposes into nitrogen and hydrogen.

The conversion of oxygen into ozone is also reversible and may be

represented thus:

oxygen <--> ozone.

~Chemical equilibrium.~ Reversible reactions do not usually go on to

completion in one direction unless the conditions under which the

reaction takes place are very carefully chosen. Thus, if iron and steam

are confined in a heated tube, the steam acts upon the iron, producing

iron oxide and hydrogen. But these substances in turn act upon each

other to form iron and steam once more. When these two opposite

reactions go on at such rates that the weight of the iron changed into

iron oxide is just balanced by the weight of the iron oxide changed into

iron, there will be no further change in the relative weights of the

four substances present in the tube. The reaction is then said to have

reached an equilibrium.

~Factors which determine the point of equilibrium.~ There are two factors

which have a great deal of influence in determining the point at which a

given reaction will reach equilibrium.

1. _Influence of the chemical nature of the substances._ If two

reversible reactions of the same general kind are selected, it has been

found that the point of equilibrium is different in the two cases. For

example, in the reactions represented by the equations

3Fe + 4H_{2}O <--> Fe_{3}O_{4} + 8H,

Zn + H_{2}O <--> ZnO + 2H,

the equilibrium will be reached when very different quantities of the

iron and zinc have been changed into oxides. The individual chemical

properties of the iron and zinc have therefore marked influence upon the

point at which equilibrium will be reached.

2. _Influence of relative mass._ If the tube in which the reaction

3Fe + 4H_{2}O <--> Fe_{3}O_{4} + 8H

has come to an equilibrium is opened and more steam is admitted, an

additional quantity of the iron will be changed into iron oxide. If more

hydrogen is admitted, some of the oxide will be reduced to metal. The

point of equilibrium is therefore dependent upon the relative masses of

the substances taking part in the reaction. When one of the substances

is a solid, however, its mass has little influence, since it is only the

extent of its surface which can affect the reaction.

~Conditions under which reversible reactions are complete.~ If, when the

equilibrium between iron and steam has been reached, the tube is opened

and a current of steam is passed in, the hydrogen is swept away as fast

as it is formed. The opposing reaction of hydrogen upon iron oxide must

therefore cease, and the action of steam on the iron will go on until

all of the iron has been transformed into iron oxide.

On the other hand, if a current of hydrogen is admitted into the tube,

the steam will be swept away by the hydrogen, and all of the iron oxide

will be reduced to iron. _A reversible reaction can therefore be

completed in either direction when one of the products of the reaction

is removed as fast as it is formed._

~Equilibrium in solution.~ When reactions take place in solution in water

the same general principles hold good. The matter is not so simple,

however, as in the case just described, owing to the fact that many of

the reactions in solution are due to the presence of ions. The

substances most commonly employed in solution are acids, bases, or

salts, and all of these undergo dissociation. Any equilibrium which may

be reached in solutions of these substances must take place between the

various ions formed, on the one hand, and the undissociated molecules,

on the other. Thus, when nitric acid is dissolved in water, equilibrium

is reached in accordance with the equation

H^{+} + NO_{3}^{-} <--> HNO_{3}.

~Conditions under which reversible reactions in solution are complete.~

The equilibrium between substances in solution may be disturbed and the

reaction caused to go on in one direction to completion in either of

three ways.

1. _A gas may be formed which escapes from the solution._ When sodium

nitrate and sulphuric acid are brought together in solution all four

ions, Na^{+}, NO_{3}^{-}, H^{+}, SO_{4}^{--}, are formed. These ions are

free to rearrange themselves in various combinations. For example, the

H^{+} and the NO_{3}^{-} ions will reach the equilibrium

H^{+} + NO_{3}^{-} <--> HNO_{3}.

If the experiment is performed with very little water present, as is the

case in the preparation of nitric acid, the equilibrium will be reached

when most of the H^{+} and the NO_{3}^{-} ions have combined to form

undissociated HNO_{3}.

Finally, if the mixture is now heated above the boiling point of nitric

acid, the acid distills away as fast as it is formed. More and more

H^{+} and NO_{3}^{-} ions will then combine, and the process will

continue until one or the other of them has all been removed from the

solution. The substance remaining is sodium acid sulphate (NaHSO_{4}),

and the reaction can therefore be expressed by the equation

NaNO_{3} + H_{2}SO_{4} = NaHSO_{4} + HNO_{3}.

2. _An insoluble solid may be formed._ When hydrochloric acid (HCl) and

silver nitrate (AgNO_{3}) are brought together in solution the

following ions will be present: H^{+}, Cl^{-}, Ag^{+}, NO_{3}^{-}. The

ions Ag^{+} and Cl^{-} will then set up the equilibrium

Ag^{+} + Cl^{-} <--> AgCl.

But silver chloride (AgCl) is almost completely insoluble in water, and

as soon as a very little of it has formed the solution becomes

supersaturated, and the excess of the salt precipitates. More silver and

chlorine ions then unite, and this continues until practically all of

the silver or the chlorine ions have been removed from the solution. We

then say that the following reaction is complete:

AgNO_{3} + HCl = AgCl + HNO_{3}.

3. _Two different ions may form undissociated molecules._ In the

neutralization of sodium hydroxide by hydrochloric acid the ions H^{+}

and OH^{-} come to the equilibrium

H^{+} + OH^{-} <--> H_{2}O.

But since water is almost entirely undissociated, equilibrium can only

be reached when there are very few hydroxyl or hydrogen ions present.

Consequently the two ions keep uniting until one or the other of them is

practically removed from the solution. When this occurs the

neutralization expressed in the following equation is complete:

NaOH + HCl = H_{2}O + NaCl.

~Preparation of acids.~ The principle of reversible reactions finds

practical application in the preparation of most of the common acids. An

acid is usually prepared by treating the most common of its salts with

some other acid of high boiling point. The mixture is then heated until

the lower boiling acid desired distills out. Owing to its high boiling

point (338°), sulphuric acid is usually employed for this purpose, most

other acids boiling below that temperature.

EXERCISES

1. What would take place when solutions of silver nitrate and sodium

chloride are brought together? What other chlorides would act in the

same way?

2. Is the reaction expressed by the equation NH_{3} + H_{2}O = NH_{4}OH

reversible? If so, state the conditions under which it will go in each

direction.

3. Is the reaction expressed by the equation 2H + O = H_{2}O reversible?

If so, state the conditions under which it will go in each direction.

4. Suggest a method for the preparation of hydrochloric acid.

An Elementary Study of Chemistry · 第 13 / 32 章