Then

___ ___

___ AD² CD²

CD x DI = AD². CD = ---- = --------- tang²[alpha],

DI CI - CD

[TEX: CD \times DI = \overline{AD^2}.\ CD = \frac{\overline{AD^2}}{DI} =

\frac{\overline{CD^2}}{CI-CD} \tan^2 \alpha]

whence

CI

CD = ------------------ or CD = CI cos²[alpha]. (1)

I + tang²[alpha]

[TEX: CD = \frac{CI}{I + \tan^2 \alpha}\ \text{or}\ CD = CI \cos^2

\alpha.]

Scientific American Supplement, No. 363, December 16, 1882 · 第 34 / 78 题