y² - 3x² + 2Dx - D²/3 + D² - 2Dx + 2D²/3 = o
[Hence] y² - 3x² = - 4D²/3
[Illustration: Fig I]
[Illustration: Fig II]
This is the equation of an hyperbola referred to its center o' as
the origin of co-ordinates. To write it in the ordinary form, that is
in terms of the transverse and conjugate axes, multiply each term by
C, i.e.,
__
Let \/C = semi-transverse axis.
[TEX: \sqrt{C} = \text{semi-transverse axis.}]