The first of equations (9) gives

[=omega]3 = 0 (10).

For =[omega]1, we have

_ _ _ -ikr

1 / / / dZ e

[=omega]1 = -------- | | | -- ----- dx dy dz (11),

4[pi]b^2 _/_/_/ dy r

where r is the distance between the element dx dy dz and the point

where [=omega]1 is estimated, and

k = n/b = 2[pi]/[lambda] (12),

[lambda] being the wave-length.

(This solution may be verified in the same manner as Poisson's

theorem, in which k = 0.)

We will now introduce the supposition that the force Z acts only

within a small space of volume T, situated at (x, y, z), and for

simplicity suppose that it is at the origin of co-ordinates that the

rotations are to be estimated. Integrating by parts in (11), we get

_ -ikr _ _ _

/ e dZ | Ze^-ikr | / d / e^-ikr\

| ------ -- dy = | ------- | - | Z -- ( ------- ) dy,

_/ r dy |_ r _| _/ dy \ r /

in which the integrated terms at the limits vanish, Z being finite

only within the region T. Thus

_ _ _ -ikr

1 / / / d /e^ \

[=omega]1 = ------- | | | Z -- ( -------- ) dx dy dz.

4[pi]b^2 _/_/_/ dy \ r /

Since the dimensions of T are supposed to be very small in comparison

with [lambda], the factor d/dy (e^-ikr / r) is sensibly constant; so

that, if Z stand for the mean value of Z over the volume T, we may

write

TZ y d / e^-ikr \

[=omega]1 = -------- . - . -- ( ------ ) (13).

4[pi]b^2 r dr \ r /

Encyclopaedia Britannica, 11th Edition, "Diameter" to "Dinarchus" Volume 8, Slice 4 · 第 77 / 86 题