Thus, if we take

_[oo]

1 / e^-ux [sqrt](x).dx

G = ----------- | ------------------,

[pi][sqrt]2 _/0 1 + x^2

_[oo]

1 / e^-ux dx

H = ----------- | ------------------ (13).

[pi][sqrt]2 _/ [sqrt]x . (1 + x^2)

0