_10. Kan._ 8. Cib. 6. Lamat. 4. Ahau. 2. Eb.
_10. Lamat._ 8. Ahau. 6. Eb. 4. Kan. 2. Cib.
_10. Eb._ 8. Kan. 6. Cib. 4. Lamat. 2. Ahau.
_10. Cib._ 8. Lamat. 6. Ahau. 4. Eb. 2. Kan.
_10. Ahau._ 8. Eb. 6. Kan. 4. Cib. 2. Lamat.
13. _Kan._ _11. Cib._ 9. Lamat. 7. Ahau. 5. Eb.
13. _Lamat._ _11. Ahau._ 9. Eb. 7. Kan. 5. Cib.
13. _Eb._ _11. Kan._ 9. Cib. 7. Lamat. 5. Ahau.
13. _Cib._ _11. Lamat._ 9. Ahau. 7. Eb. 5. Kan.
13. _Ahau._ _11. Eb._ 9. Kan. 7. Cib. 5. Lamat.
3. Kan. 1. _Cib._ _12. Lamat._
3. Lamat. 1. _Ahau._ _12. Eb._
3. Eb. 1. _Kan._ _12. Cib._
3. Cib. 1. _Lamat._ _12. Ahau._
3. Ahau. 1. _Eb._ _12. Kan._
An inspection of this table shows us that the five days repeated in each
column are the same as those on the right of the quadrilateral of our
scheme (Fig. 2), and are exactly in the order obtained by arranging the
days of the month in four columns in the manner heretofore shown. (See
column 4, Table IV.)
If I am correct in my supposition, we then have one clue to, if not a
full explanation of, the method of obtaining the day columns in the
Manuscript Troano.
[Illustration: FIG. 3.--Copy from Plates 18 and 19, Codex Peresianus.]
Not this only, for this table of the Codex Peresianus furnishes us also
the explanation of the red numerals found over the day columns in the
Manuscript Troano. Take, for example, Plate XIX, first or upper
division, given also in my Study of The Manuscript Troano, p. 176, here
the number is IV, corresponding with column 4 of the above table (V),
where the days are the same and the numeral prefixed to each day is 4.
Plate XXVI (Study Manuscript Troano, p. 177), lower division, the days
are the same and the number over the column is XIII, corresponding with
the sixth column of Table V. This corroborates the opinion I expressed
in my former work, that the number over the column was to be applied to
each day of the column.
Why is the order of the numerals in the extract from the Codex
Peresianus precisely the same as the numbering of the Ahaues? I answer,
because each column, if taken as referring to the four classes of years,
will, when the number of the month is given, determine just the years of
an Ahau; or a fancy of the artist to follow an order considered sacred.
To illustrate, let us take the next to the right-hand column of the
table where the numeral is 1, and let us assume the month to be Pop, or
the 1st. Then we have 1 Cib, 1 Ahau, 1 Kan, 1 Lamat, and 1 Eb of the
first month, and from this data we are to find the years. As there can
be four years found to each of these days, that is a Cauac year with 1
Cib in the first month, a Muluc year with one Cib in the first month, a
Kan year with one Cib in the first month, an Ix year with one Cib in the
first month, a Kan year with one Ahau in the first month, &c., it is
evident that there will be, as the total result, just twenty years.
As I cannot repeat here, without occupying too much space, the method of
finding the years, I must refer the reader to Study Manuscript Troano,
p. 23, _et al._ Hunting them out, by using our Table III, we find them
to be as follows:
1 _Cib._ 1 _Ahau._ 1. _Kan._ 1. _Lamat._ 1 _Eb._[TN-8]
Years 10 Cauac. 13 Cauac. 9 Cauac. 5 Cauac. 1 Cauac.
Years 2 Kan. 11 Kan. 1 Kan. 10 Kan. 6 Kan.
Years 7 Muluc. 3 Muluc. 12 Muluc. 8 Muluc. 11 Muluc.
Years 12 Ix. 8 Ix. 4 Ix. 13 Ix. 9 Ix.
If we turn now to Table XVII (Study Manuscript Troano p. 44), we will
find that these are precisely the counted years (those in the space
inclosed by the dotted lines) in Ahau number VI.
If we assume the month to be the 11th then the numbers of the Ahaues
will correspond exactly with the numbers of the columns of our Table
V.[8]
As it may be supposed that using the same numeral to any five days of
the twenty in this way will produce a similar result, let us test it by
an example. For this purpose we select the same column of our foregoing
table, No. V--that with the number 1 prefixed--Cib, Ahau, Kan, Lamat,
Eb, but in place of Lamat we insert Cimi. Hunting out the years as
heretofore we find them to be as follows:
1 _Cib._ 1 _Ahau._ 1 _Kan._ 1 _Cimi._ 1 _Eb._
Years 10 Cauac. 13 Cauac. 9 Cauac. 7 Cauac. 1 Cauac.
Years 2 Kan[TN-9] 11 Kan. 1 Kan. 12 Kan. 6 Kan.
Years 7 Muluc. 3 Muluc. 12 Muluc. 10 Muluc. 11 Muluc.
Years 12 Ix. 8 Ix. 4 Ix. 2 Ix. 9 Ix.
If we try to locate these years in an Ahau in Table XVII (Study
Manuscript Troano p. 44), we shall find it impossible to do so, nor can
we locate them in any table that can be made which has either
twenty-four or twenty years in an Ahau, while on the other hand the
twenty years obtained by using a column of the table from the Codex
Peresianus can be located in some one of the Ahaues obtained by any
division of the Grand Cycle into consecutive groups of twenty-four years
that can be made. It would require too much space to prove this
assertion, but any one who doubts its correctness can test it.
As the extract we have given from the Codex Peresianus relates only to
one of the four groups of days--that on the right of the
quadrilateral--I will supply in the following tables, Nos. VII, VIII,
and IX, the arrangement of the groups of the other three sides; adding
the other (Table VI), also, so as to bring the four together in the
order of the sides of the quadrilateral, commencing with the line on the
right, next the upper one, and so on.
While this is undoubtedly the order in which they are to be taken; which
is the proper one to commence with? is a question yet to be discussed.