If of _Water_, whose Refraction is as 4 to 3, the Theorem will stand thus

(_12drρ - 3dρt + 9rρt_)/(_4dr + 4dρ - 12rρ - dt + 3rt_) = _f_.

If it could be made of _Diamant_, whose Refraction is as 5 to 2, it

would be

(_(10/3)drρ - 2dρt + (4/3)rρt_)/(_5dr + 5dρ - (10/3)rρ - 3dt

+ 2rt_) = _f_.

And this is the universal Rule for the _Foci_ of double Convex Glasses

exposed to diverging Rays. But if the thickness of the _Lens_ be

rejected, as not sensible, the Rule will be much shorter, _viz._

_pdrρ_/(_dr + dρ - prt_) = _f_,

or in Glass

_2drρ_/(_dr + dρ - 2rρ_) = _f_,

all the Terms wherein _t_ is found being omitted, as equal to nothing.

In this Case, if _d_ be so small, as that _2rρ_ exceed _dr + dρ_,

then will it be - _f_, or the _Focus_ will be Negative, which shews that

the Beams after both Refractions still proceed diverging.

To bring this to the other Cases, as of converging Beams, or of Concave

Glasses, the Rule is ever composed of the same Terms, only changing the

Signs of + and -; for the distance of the Point of Concourse of

converging Beams, from the Point B, or the first Surface of the _Lens_,

I call a negative Distance or - _d_; and the Radius of a Concave _Lens_

I call a negative Radius, or - _r_ if it be the first Surface, and - ρ

if it be the second Surface. Let then converging Beams fall on a double

Convex of Glass, and the Theorem will stand thus

- _2drρ_/(- _dr - dρ - 2rt_) = + _f_,

which shews that in this Case the _Focus_ is always affirmative.

If the _Lens_ were a _Meniscus_ of Glass, exposed to diverging Beams,

the Rule is

- _2drρ_/(- _dr + dρ + 2rρ_) = _f_,

which is affirmative when _2rρ_ is less than _dr - dρ_ otherwise

negative: But in the Case of converging Beams falling on the same

_Meniscus_, 'twill be

+ _2drρ_/(+ _dr - dρ + 2rp_) = _f_,

and it will be + _f_, whilst _dρ - dr_ is less than _2rρ_; but if it

be greater than _2rρ_, it will always be found negative or - _f_. If

the _Lens_ be double Concave, the _Focus_ of converging Beams is

negative, where it was affirmative in the Case of diverging Beams on a

double Convex, _viz._

- _2drρ_/(+ _dr + dρ - 2rρ_) = _f_,

which is affirmative only when _2rρ_ exceeds _dr + dρ_: But

diverging Beams passing a double Concave, have always a negative

_Focus_, _viz._

- _2drρ_/(+ _dr + dρ + 2rρ_) = - _f_.

The Theorems for converging Beams, are principally of use to determine

the _Focus_ resulting from any sort of _Lens_ placed in a Telescope,

between the _Focus_ of the Object-Glass and the Glass it self; the

distance between the said _Focus_ of the Object-Glass, and the

interposed _Lens_ being made = - _d_.

I here suppose my Reader acquainted with the Rules of Analytical

Multiplication and Division, as that + multiplied by + makes the Product

+, + by - makes -, and - by - makes +; so dividing + by + makes the

Quote +, + by - makes -, and - by - makes +; which will be necessary to

be understood in the preceding Examples.

In case the Beams are parallel, as coming from an infinite distance,

(which is supposed in the Case of Telescopes) then will _d_ be supposed

Infinite, and in the Theorem

_pdρr_/(_dr + dρ - prρ_)

the Term _prρ_ vanishes, as being finite, which is no part of the

other infinite Terms; and dividing the Remainder by the infinite Part

_d_, the Theorem will stand thus _pρr_/(_r + ρ_) = _f_, or in Glass,

_2rρ_/(_r + ρ_) = _f_.

In case the _Lens_ were _Plano-Convex_ exposed to diverging Beams,

instead of _pdρr_/(_dr + dρ - prρ_), _r_ being infinite, it will

be _pdρ_/(_d - pρ_) = _f_, or _2dρ_/(_d - 2ρ_) if the _Lens_ be

Glass.

If the _Lens_ be Double-Convex, and _r_ be equal to ρ, as being formed

of Segments of equal Spheres, then will (_pdρr_)/(_dr + dρ - prρ_)

be reduced to (_pdr_/(_2d - pr_))_f_; and in case _d_ be infinite, then

it will yet be farther contracted to ½_pr_, and _p_ being = _n_/(_m

- n_), the focal distance in Glass will be = _r_, in Water 1½_r_,

but in Diamant ⅓_r_.

I am sensible that these Examples are too much for the compleat Analyst,

though I fear too little for the less Skilful; it being very hard, if

possible, in such Matters, so to write, as to give satisfaction to both;

or to please the one, and instruct the other. But this may suffice to

shew the extent of our Theorem, and how easie a Reduction adapts any one

case to all the rest.

Nor is this only useful to discover the _Focus_ from the other proposed

_data_, but from the _Focus_ given, we may thereby determine the

distance of the Object; or from the _Focus_ and Distance given, we may

find of what Sphere it is requisite to take another Segment, to make any

given Segment of another Sphere cast the Beams from the distance _d_ to

the _Focus_ _f_. As likewise from the _Lens_, _Focus_, and Distance

given, to find the _Ratio_ of Refraction, or of _m_ to _n_, requisite to

answer those _Data_. All which it is obvious, are fully determined from

the Equation we have hitherto used, _viz._

_pdρr_ = _drf + dρf - prρf_,

for to find _d_ the Theorem is (_prρf_)/(_rf + ρf - pρr_) = _d_,

the distance of the Object.

Miscellanea Curiosa, Vol. 1 Containing a collection of some of the principal phaenomena in nature, accounted for by the greatest philosophers of this age · 第 24 / 38 题