No values exist for _x_ and _y_, so that the equation

_F_ = _x_ + _y R_

shall be satisfied for all pairs of values of _F_ and _R_, but the best

values for _x_ and _y_ are those which make

(_F₁_ - _x_ - _y R₁_)² + (_F₂_ - _x_ - _y R₂_)² + &c.

+ (_Fₘ_ - _x_ - _y Rₘ_)²

a minimum.

Differentiating with respect to _x_ and _y_, and equating the

differential coefficients to zero, we have

Σ (_F₁_ - _x_ - _y R₁_) = 0,

Σ _R₁_(_F₁_ - _x_ - _y R₁_) = 0.

This gives two equations for the determination of _x_ and _y_.

Suppose, as is usually the case, the loads be of the form,

_N_, 2_N_, 3_N_, 4_N_ &c. _mN_,

and making

_A_ = _F₁_ + _F₂_ + _F₃_ + &c. + _Fₘ_

_B_ = _F₁_ +2_F₂_ + 3_F₃_ + &c. + _mFₘ_,

we have the equations

_m_(_m_ + 1)

_A_ - _mx_ - ————————————— _N y_ = 0,

2

_m_(_m_ + 1) _m_(_m_ + 1) (2_m_ + 1)

_B_ - ————————————— _x_ - ——————————————————————— _N y_ = 0.

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Experimental Mechanics A Course of Lectures Delivered at the Royal College of Science for Ireland · 第 165 / 171 题