11. The equation is

x^n - p1x^(n-1) + ... [+-]p_n = 0,

and we here _assume_ the existence of roots, viz. we assume that there

are n quantities a, b, c ... (in general all of them different, but

which in particular cases may become equal in sets in any manner), such

that

x^n - p1x^(n - 1) + ... [+-] p_n = 0;

or looking at the question in a different point of view, and starting

with the roots a, b, c ... as given, we express the product of the n

factors x - a, x - b, ... in the foregoing form, and thus arrive at an

equation of the order n having the n roots a, b, c.... In either case we

have

p1 = [Sigma]a, p2 = [Sigma]ab, ... p_n = abc ...;

i.e. regarding the coefficients p1, p2 ... p_n as given, then we assume

the existence of roots a, b, c, ... such that p1 = [Sigma]a, &c.; or,

regarding the roots as given, then we write p1, p2, &c., to denote the

functions [Sigma]a, [Sigma]ab, &c.

As already explained, the epithet algebraical is not used in

opposition to numerical; an algebraical equation is merely an equation

wherein the coefficients are not restricted to denote, or are not

explicitly considered as denoting, numbers. That the abstraction is

legitimate, appears by the simplest example; in saying that the

equation x^2 - px + q = 0 has a root x = 1/2{p + [root](p^2 - 4q)}, we

mean that writing this value for x the equation becomes an identity,

[1/2{p + [root](p^2 - 4q)}]^2 - p[1/2{p + [root](p^2 - 4q)}] + q = 0;

and the verification of this identity in nowise depends upon p and q

meaning numbers. But if it be asked what there is beyond numerical

equations included in the term algebraical equation, or, again, what

is the full extent of the meaning attributed to the term--the latter

question at any rate it would be very difficult to answer; as to the

former one, it may be said that the coefficients may, for instance, be

symbols of operation. As regards such equations, there is certainly no

proof that every equation has a root, or that an equation of the nth

order has n roots; nor is it in any wise clear what the precise

signification of the statement is. But it is found that the assumption

of the existence of the n roots can be made without contradictory

results; conclusions derived from it, if they involve the roots, rest

on the same ground as the original assumption; but the conclusion may

be independent of the roots altogether, and in this case it is

undoubtedly valid; the reasoning, although actually conducted by aid

of the assumption (and, it may be, most easily and elegantly in this

manner), is really independent of the assumption. In illustration, we

observe that it is allowable to express a function of p and q as

follows,--that is, by means of a rational symmetrical function of a

and b, this can, as a fact, be expressed as a rational function of a +

b and ab; and if we prescribe that a + b and ab shall then be changed

into p and q respectively, we have the required function of p, q. That

is, we have F([alpha], [beta]) as a representation of [f](p, q),

obtained as if we had p = a + b, q = ab, but without in any wise

assuming the existence of the a, b of these equations.

Encyclopaedia Britannica, 11th Edition, "Equation" to "Ethics" Volume 9, Slice 7 · 第 18 / 52 题