Let

α = the angular radius in seconds of arc

_d_ = the distance in light-years

ρ = the density in terms of earth’s atmosphere at sea-level

_v_ = the linear velocity of rotation in km/sec.

Then the following relations hold:

(1) _M_ = 3.4 × 10⁻⁴ _d_α_v_²

(2) ρ = 1.4 × 10⁻⁶ (_v_/_d_α)²

(3) _P_ = 9.15 _d_α/_v_

The velocity of escape for the nebula is proportional to α/ρ and

hence to _v_. This follows from the assumption that the particles are

rotating in equilibrium, and therefore the factor of proportionality is

the ratio between parabolic and circular velocity, that is, 1.4, and is

independent of the distance. The value of _v_ for those nebulae so far

observed is small, ranging from 5 to 10 km. Hence, if the assumptions

held only approximately, the velocity of escape would be small and

of the same order as that for the earth. Since these nebulae are

composed of the lightest gases, it follows that at any save very low

temperatures the molecules would escape at a very rapid rate. Certainly

the nebulae would dissipate if the temperatures were of the order of

that of our own atmosphere.

Photographic investigations of faint nebulae · 第 13 / 41 题