_To find the distance of the Sun and Moon from the Nodes, at the time of
Full Moon in_ March, _the year before_ CHRIST _721, O. S._
The years 720 added to 1780 make 2500, or 25 Centuries.
Sun from Node
s ° ʹ
To the mean time of Full Moon in _March 1780_, Table III. 10 3 1
Add the distance for 1 Lunation [See _N. B._ Page 195,
and Example III, Page 198] 1 0 40
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Sum 11 3 41
From which subtract the Sun’s distance from the Node
for 2500 years, Table V 5 4 11
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Remains the Sun’s distance from the Node, _March 19_,
721 years before CHRIST 5 29 30
To which add 6 Signs for the Moon’s distance, because
she was then in opposition to the Sun 6 0 0
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The Sum is the Moon’s dist. from the Ascend. Node 11 29 30
That is, she was within half a degree of coming round to it again; and
therefore, being so near, she must have been totally, and almost
centrally eclipsed.