s ° ʹ
Sun from Node at Full Moon in _March 1761_ 9 25 27
Add his distance for two Lunations, to bring it into _May_ 2 1 20
---------
And his distance at Full Moon in that month is 11 26 47
Subtract this from a Circle, or 12 Signs, and there will remain 3° 13ʹ;
which is all that the Sun wants of coming round to the Ascending Node;
and the Moon being then opposite to the Sun, must be just as near the
Descending Node: consequently, far within the limit of an Eclipse.
384. Knowing then that the Moon will be eclipsed in _May 1761_, we must
find her true distance from the Node at that time, by applying the
proper Equations as taught § 363, and then find her true Latitude as
taught in that article.
[Sidenote: Table IV.
Table XIII.