_To find the time of Full Moon at_ Babylon _in_ March, _the year before
Christ 721_.
The years 720 added to 1780 make 2500, or 25 Centuries.
+------------------------------------+----------+-------------+-------------+
| | | Sun’s Anom. | Moon’s Ano. |
| | D. H. M. +-------------+-------------+
| | | s ° ʹ | s ° ʹ |
| +----------+-------------+-------------+
| Tab. I. To the mean F. Moon and | | | |
| Anom. in _Mar. 1780_ | 9 4 41 | 8 19 48 | 7 8 10 |
| Add one Lunation and it’s | | | |
| Anomalies from Tab. VI[80] | 29 12 44 | 0 29 6 | 0 25 49 |
| | -------- | ---------- | ---------- |
| The several sums are | 38 17 25 | 9 18 54 | 8 3 59 |
| Fr. which subt. the Days & Anom. | | | |
| of 2500 years, Tab. V | 19 22 20 | 11 26 19 | 6 6 43 |
| | -------- | --------- | ---------- |
| Rem. the mean time and Anom. of | | | |
| F.M. in _Mar. b.C. 721_ | 18 19 5 | 9 22 25 | 1 27 16 |
| To which add the sum of the | +-------------+ |
| three Equations | + 11 36 | Equ. Moon’s Anom. - 18 |
| | -------- | Anom. cor. 1 26 48 |
| And it gives the true time of | | Sun’s Equat. + 1 47 |
| Full Moon, _Mar. b.C. 721_ | 18 6 41 | ---------- |
| +------+---+ Moon’s Anom. 1 28 35 |
| Which was the 19th day, at 41 minutes +-------------------------------+
| past 6 in the evening, at _London_; | Moon’s ann. Eq. 0^h 20^m add |
| to which time, if[81] 2 hours 51 | Her ellipt. Equ. 8 1 add |
| minutes be added, we shall have | Sun’s Equation 3 15 add |
| the time at _Babylon_, namely, | Sum 11 36 add |
| 9 hours 51 minutes. | |
+-------------------------------------------+-------------------------------+
357. To know whether the Sun will be eclipsed or no, at the time of any
given New Moon; collect the Sun’s distance from the Node at that time,
and if it be less than 17 degrees he will be eclipsed, otherwise not.