_To find the time of New Moon at_ London _and_ Athens _in_ March, _the
year before Christ 424._
The years 423 added to 1777 make 2200, or 22 Centuries.
+------------------------------------+----------+-------------+-------------+
| | | Sun’s Anom. | Moon’s Ano. |
| | D. H. M. +-------------+-------------+
| | | s ° ʹ | s ° ʹ |
| +----------+-------------+-------------+
| Tab. I. Mean New Moon in _March_ | | | |
| A. D. 1777 | 27 7 53 | 9 7 27 | 5 25 51 |
| From which subtract 2200 years | | | |
| in Tab. V. | 6 21 47 | 11 16 26 | 4 20 37 |
| | -------- | ---------- | ---------- |
| Mean Conj. and Anom. in _March_ | | | |
| before Chr. 424 | 20 10 6 | 9 21 1 | 1 5 14 |
| Which with, the total of the three | +-------------+ |
| Equations added | 9 20 | Equ. Moon’s Anom. - 19 |
| | -------- | ---------- |
| Gives the true time of Conjunction | 20 19 26 | Anom. cor. 1 4 55 |
| +----------+ Sun’s Equat. + 1 48 |
| Which was the 21st day of _March_, at | --------- |
| 26 minutes past 7 in the morning at | Moon’s Ano. 1 6 43 |
| _London_: and if 1 hour 35 minutes +---+---------------------------+
| be added for _Athens_, which is 23° 52ʹ | Moon’s ann. Eq. 0^h 20^m add |
| east of the meridian of _London_, we | Her ellipt. Equ. 5 43 add |
| have the time at _Athens_; namely, | Sun’s Equation 3 17 add |
| 1 minute past 9 in the morning. | Total 9 20 add |
+-------------------------------------------+-------------------------------+