EXAMPLE I.

_To find the time of New Moon in_ July 1581, _O. S._

From 1781 subtract 200 years, and there remains 1581.

+-----------------------------------+-----------+-------------+-------------+

| | | Sun’s Anom. | Moon’s Ano. |

| | D. H. M. +-------------+-------------+

| | | s ° ʹ | s ° ʹ |

| +-----------+-------------+-------------+

| Table I. Mean time of New Moon | | | |

| in _March 1781_ | 13 7 52 | 8 23 37 | 0 0 53 |

| Tab. V. Conj. and Anom. for 200 | | | |

| years subtract | 8 16 22 | 0 6 42 | 5 0 44 |

| | --------- | ---------- | ---------- |

| Remain the Conj. and Anom. for | | | |

| _March 1581_ | 4 15 30 | 8 16 55 | 7 0 9 |

| Tab. VI. Add, for five Lunations, | | | |

| to bring it to _July_ | 147 15 40 | 4 25 32 | 4 9 5 |

| | --------- | ---------- | ---------- |

| The sums are | 152 7 10 | 1 12 27 | 11 9 14 |

| +-----------+-------------+ |

| The Days in Tab. VII. answer | | Equ. Moon’s Anom. + 13 |

| to _July_ 30th | 30 7 10 | ----------- |

| Sum of the three Equations | | Anom. cor. 11 9 27 |

| subtract | - 7 9 | Sun’s Equat. - 1 16 |

| | --------- | ----------- |

|True time of Conjunction, _July_ | 30 0 1 | Moon’s Ano. 11 8 11 |

| +-----+-----+---------------------------+

| Which is the 30th day, at one minute | Moon’s ann. Eq. 0^h 14^m sub. |

| past noon, as shewn by well | Her ellipt. Equ. 3 35 sub. |

| regulated Clocks or Watches | Sun’s Equation 3 20 sub. |

| | ------------- |

| | Sum 7 9 sub. |

+-----------------------------------------+---------------------------------+

Astronomy Explained Upon Sir Isaac Newton's Principles And made easy to those who have not studied mathematics · 第 203 / 275 题