VII. Subtract VI. from 7; this is the number of the dominical letter

1 2 3 4 5 6 7 (7; dominical letter G).

A B C D E F G

VIII. Divide I. by 19, the remainder (or 19, if no remainder) is the

_golden number_. (7).

IX. From the centurial figures of the year subtract 17, divide by 25, and

keep the quotient. (0).

X. Subtract IX. and 15 from the centurial figures, divide by 3, and keep

the quotient. (1).

XI. To VIII. add ten times the next less number, divide by 30, and keep the

remainder. (7).

XII. To XI. add X. and IV., and take away III., throwing out thirties, if

any. If this give 24, change it into 25. If 25, change it into 26, whenever

the golden number is greater than 11. If 0, change it into 30. Thus we have

the epact, or age of the _Calendar_ moon at the beginning of the year. (6).

_When the Epact is 23, or less._

A Budget of Paradoxes, Volume I · 第 175 / 198 题