PERPETUAL CALENDAR

To find the day of the week for any given date.

1. Take the last two figures of the year, add one-fourth of them

(neglecting remainder). Thus: 1949 = 49 + 12 = 61.

2. Add for the month, if for January or October, 1; May, 2; August, 3;

February, March, or November, 4; June, 5; September or December, 6;

April or July, 0; if leap year (that is, if it be divisible by 4 without

remainder) January 0; February 3.

The Circle of Knowledge: A Classified, Simplified, Visualized Book of Answers · 第 1248 / 1638 题