TABLE VII.

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GROSS AND EFFICIENT POWER OF 12 AND 14 FOOT WINDMILLS.

-------------------------+----------+--------------+-------------

| Velocity | Gross | Net

SIZE OF MILL. | of Wind. | Horse-power. | Horse-power.

-------------------------+----------+--------------+-------------

12-Foot Ideal Power Mill | 10 Miles | 1/2 | 1/10

12 „ „ „ „ | 15 „ | 1 | 3/5

12 „ „ „ „ | 20 „ | 2 | 1-3/5

12 „ „ „ „ | 25 „ | 3 | 2-3/5

14 „ „ „ „ | 10 „ | 1 | 3/5

14 „ „ „ „ | 15 „ | 2 | 1-3/5

14 „ „ „ „ | 20 „ | 4 | 3-3/5

14 „ „ „ „ | 25 „ | 6 | 5-3/5

-------------------------+----------+--------------+-------------

The preceding tables are based upon tests of the _Sampson windmill_

as compiled by its makers, The Stover Manufacturing Co.; they deserve

careful study by those planning the introduction of aermotors.

_The power of a windmill_ depends—first, on the diameter of the

wheel; and second, on the velocity of wind. _To increase the diameter

of the wheel is to increase its power_ in proportion to the area of

the squares. Table I gives the horse-power of several sizes of mills

working in a fifteen-mile wind: if the wind velocity be increased or

diminished, the power of the windmill will increase or decrease in the

ratio of the squares of the velocity. Table V will show the comparative

power or force of the wind in velocities from eight to forty miles per

hour for each square foot of surface.

_Rules for approximately determining size of windmill to use._

The daily water consumption must be given as a basis for calculation.

Divide this by 8 to find the hourly capacity of windmill, as if loaded

aright the mill will pump on an average eight hours daily.

_Multiply the quotient by total water lift in feet and with the

co-efficient given in Table II._

The product will in Table I show what mill to use.

The size of the cylinder and discharge pipe will be found in Table III.

[Illustration: FIG. 466.]

Table I gives the maker’s number of the pumping mill, and the number

of gallons each will raise one foot high per hour, with a wind having

a velocity of fifteen miles per hour. Example: No. 9 pump will raise

24,000 gallons of water one foot high in one hour. Now if the water is

to be raised 50 feet then by dividing 24,000 by 50 the quantity raised

becomes 480 gallons per hour.

From Table V it will be seen also that a wind velocity of fifteen miles

per hour develops a power three times as great as an eight-mile wind,

and a twenty-mile wind is twice as powerful as a fifteen-mile, or six

times that of an eight-mile. Hence, _a small increase in velocity

greatly increases the power of the windmill_, while a low velocity

gives but little working force.

From Table VI it is seen that a twenty-five mile wind gives six times

as much power as a ten-mile wind, but really gives twenty-six times

_the net efficient power of the ten-mile wind_, therefore it will not

be proper to calculate on using a power windmill in as low a velocity

as ten miles.

From Table VII it is seen that the net efficient result is six

times as great in a fifteen-mile wind as in a ten-mile wind, and

sixteen times greater in a twenty-mile wind than in a ten-mile wind.

Therefore, _power windmills give best results when working in fifteen

to twenty-five mile winds_. A 12-foot power windmill working in a

fifteen-mile wind will do more work than an average horse, and when

working in a twenty-mile wind will do more work than two average horses.

_Example._—A person in Atlanta, Ga. uses 2,600 gallons of water

daily. He has a well in which the water stands 30 feet from ground

level. To obtain pressure, the water is to be elevated into a tank 50

feet above ground. 2,600 ÷ 8 = 325 gallons to be pumped hourly when

windmill works.

Average wind velocity at Atlanta is 9 miles per hour, answering to

coefficient 1.4 in Table II, and total water lift is 30 + 50 = 80

feet. 325 × 1.4 × 80 = 36,400 gallons.

If first estimate of 2,600 gallons daily was liberal, so that for

instance 2,400 gallons would be sufficient, Table I shows that a

10-foot mill can be used, but to keep on the safe side, choose a

12-foot mill. 325 gallons hourly gives us in Table III 3-1/4-inches

cylinder with 2-inches discharge pipe as proper sizes. If the 10-foot

mill is chosen take the 3-inch cylinder.

A 14-foot windmill working in a fifteen-mile wind will do more work

than two average horses, and when working in a twenty-mile wind will do

more work than four good horses, while in a twenty-five mile wind it

will do more work than six good horses.

_Giving the above tables a practical application_, a little thought

will disclose what a wealth of power stands unappropriated and ready at

hand to do many of the drudgeries of work for which large expenditures

are annually made.

The uses of power windmills are so well understood that it seems out

of place to elaborate upon them; the brief space allowed to giving

information as to the power of this class of mills when working in

different wind velocities, is best expressed in tabular form, Table VI.

Fig. 466 represents the working barrel of a _deep well pump_, such as

are used frequently in connection with the larger sizes of aermotors.

The tube is usually made of heavy brass—this is _drawn_ so perfectly,

as to size and smoothness, that a re-boring is not needed.

The plunger is here shown with four cup leather packings, with one ball

valve; the bottom valve is also a ball with the seat resting within a

conical coupling at the bottom, this with a leather packing makes a

water tight joint.

Should any accident happen to the bottom valve it may be withdrawn by

lowering the sucker-rod until the threaded portion comes in contact

with the nut underneath the plunger. By turning the sucker-rod the

nut engages the thread on the top of the lower valve-cage. Then by

withdrawing the sucker-rod both valves may be drawn up for examination

or repairs.

ROTARY AND

CENTRIFUGAL

PUMPS

[Illustration: FIG. 467.]

[Illustration: FIG. 468. (See page 199.)]

Pumps and Hydraulics, Part 2 (of 2) · 第 119 / 185 题