In this symmetrical motion

d / 1 d[psi] \ d / 1 d[psi]\

[xi] = 0, [eta] = 0, 2[zeta] = -- ( --- ------ ) + -- ( --- ------ )

dx \ y dx / dy \ y dy /

1 /d²[psi] d²[psi] 1 d[psi]\ 1

= --- ( ------- + ------- - --- ------ ) = - ---[nabla]²[psi], (2)

y \ dx² dy² y dy / y

suppose; and in steady motion,

dH 1 d[psi] dH 1 d[psi]

-- + --- ----- [nabla]²[psi] = 0, -- + --- ------ [nabla]²[psi] = 0, (3)

dx y² dx dy y² dy

so that

Encyclopaedia Britannica, 11th Edition, "Hydromechanics" to "Ichnography" Volume 14, Slice 2 · 第 38 / 120 题