GM = GG1cot[theta] = mc(P/W), (1)

and GM is called the metacentric height; and the ship must be

ballasted, so that G lies below M. If G was above M, the tangent drawn

from G to the evolute of B, and normal to the curve of buoyancy, would

give the vertical in a new position of equilibrium. Thus in H.M.S.

"Achilles" of 9000 tons displacement it was found that moving 20 tons

across the deck, a distance of 42 ft., caused the bob of a pendulum 20

ft. long to move through 10 in., so that

240 20

GM = --- × 42 × ---- = 2.24 ft.; (2)

10 9000

also

cot [theta] = 24, [theta] = 2°24´. (3)

In a diagram it is conducive to clearness to draw the ship in one

position, and to incline the water-line; and the page can be turned if

it is desired to bring the new water-line horizontal.

Suppose the ship turns about an axis through F in the water-line area,

perpendicular to the plane of the paper; denoting by y the distance of

an element dA if the water-line area from the axis of rotation, the

change of displacement is [sum]ydA tan[theta], so that there is no

change of displacement if [sum]ydA = 0, that is, if the axis passes

through the C.G. of the water-line area, which we denote by F and call

the centre of flotation.

Encyclopaedia Britannica, 11th Edition, "Hydromechanics" to "Ichnography" Volume 14, Slice 2 · 第 9 / 120 题