Experiment No. I

Flask No. I Manganese dioxide 150 m.g.

N/10 nitric acid 14.28 c.c.

[= Mn. in KMnO₄ in No. II or No. III]

Water, 27.12 c.c.

[Total solution = 41.40 c.c.]

Flask No. II

Potassium permanganate, 20 c.c. = 112.48 m.g. KMnO₄.

N/10 nitric acid 7.14 c.c. [= K in KMnO₄]

Water, 14.26 c.c.

[Total solution = 41.40 c.c.]

Flask No. III

Potassium permanganate, 20 c.c. = 112.48 m.g. KMnO₄.

N/10 nitric acid 21.40 c.c. [= K + Mn in KMnO₄]

Manganese dioxide 150 m.g.

The nitric acid in No. I is calculated to be the same as that remaining

free after the potassium of the permanganate in No. III has been

neutralized. It will be clear that the quantities of free nitric acid

are the same in flask No. I and in flask No. III provided the potassium

of the permanganate is appropriated by the nitric acid. Moreover each

flask contains the same quantity of manganese dioxide and the volume of

the liquid is the same in both.

On the other hand flask No. III contains permanganic acid. This

arrangement was selected in order to determine how far the evolution

of oxygen was influenced by the action of nitric acid on the manganese

dioxide or by the spontaneous decomposition of permanganic acid. It

was thought that if more oxygen should be obtained from flask No. III

containing a mixture of permanganate, manganese dioxide and nitric

acid, than from mixtures No. I and No. II, the larger volume must be

due to the reduction of the permanganate by the manganese oxide.

The three flasks after having been filled as described were attached to

the apparatus and then all submerged to the same depth in the boiling

water of a single glass water-bath. The stop-cocks of the azotometers

were then opened and the mercury allowed to fall to within about fifty

millimetres of its level in the reservoirs. This difference in level

was maintained as nearly as practicable by lowering the reservoirs

commenserably with the increase in gas volume. No action could be

observed in flasks No. I and No. II during the whole course of the

experiment. The contents of flask No. III however gave off bubbles of

oxygen immediately, the mercury fell in the azotometer and the dark

purple of the permanganate solution in flask No. III became rapidly

lighter. Within about five minutes it was reduced to a delicate pink

but this tint persisted for about ten minutes when it also disappeared.

Immediately after the disappearance of the permanganate color the

solution was filled with a brown oxide which remained for about

thirty five minutes when it subsided leaving the supernatant liquid

clear. Notwithstanding the fact that the color of the permanganate

had entirely disappeared and the suspended oxide had subsided within

an hour after beginning the experiment, the flasks in the earlier

experiments were allowed to remain for two hours longer. By admitting

distilled water through the tube =D= [see figure] the gas was then

forced over into the azotometer. Finally, the oxygen was determined in

the manner previously described.

The following illustration from the first experiment may serve to show

the method of calculating the results.

I II III

Total air and oxygen = 42.60 c.c. 52.40 c.c. 60.60 c.c.

Nitrogen after absorption

of oxygen = 34.00 c.c. 40.90 c.c. 37.80 c.c.

Oxygen = 8.60 c.c. 11.50 c.c. 22.80 c.c.

Air = 79.8% nitrogen

20.2% oxygen

Oxygen of air 20.2

-------------- × ---- = 8.60 c.c. 10.353 c.c. 9.57 c.c.

Nitrogen found 79.8

Oxygen obtained = 0.0 1.147 c.c. 13.23 c.c.

Temperature = 21°C.

Barometer = 737 mm.

Oxygen obtained at Normal = 0 1.033 c.c. 11.913 c.c.

The 20 c.c. KMnO₄ = 112.48 m.g.

1 atom of oxygen = 7.967 c.c.

Atoms oxygen found I II III

from the molecule KMnO₄ = 0 0.129 1.496

As at the end of the preceding calculation the results are expressed

in the table following in terms of oxygen atoms obtained from each

molecule of potassium permanganate [KMnO₄] reduced. Thus an equivalent

of one atom of oxygen from one molecule of potassium permanganate

would equal 15.96/157.67 of the weight of potassium permanganate used

in the experiment. This weight divided by the weight of one cubic

centimetre of oxygen gives the number of cubic centimetres of oxygen at

normal, equivalent to one atom of oxygen from one molecule of potassium

permanganate. The results obtained are tabulated as follows:

Three-hour determinations.

-------------------+-------------------------+----------------------

Flask I | Flask II | Flask III

-------------------+-------------------------+----------------------

MnO₂ N/10 HNO₃| KMnO₄ N/10 HNO₃ | KMnO₄ N/10 HNO₃

[150 m.g.] No. of | 20 c.c. = No. of | 20 c.c. = No. of

molecules | 112.48 m.g. molecules | 112.48 m.g. molecules

-------------------+-------------------------+----------------------

1 0.00 2 0.13 1 1.495 3

2 0.00 ” ? 1 1.493 ”

3 ” 0.13 3 1.532* ”

4 0.00 ” 0.21 ” 1.466 ”

5 0.03 ” 0.10 ” 1.467 ”

6 0.02 ” 0.25 ” ”

7 0.06 ” 0.08 ” 1.526* ”

8 0.04 ” 0.15 ” 1.527 ”

9 0.04 ” 0.11 ” 1.504 ”

10 ” 0.20 ” 1.504 ”

11 0.03 ” 0.14 ” 1.516 ”

12 0.00 ” 0.18 ” 1.524 ”

13 0.03 ” 0.25 ” 1.559* ”

14 0.05 ” 0.26 ” 1.574 ”

15 0.02 1 0.32 2 1.552 2

16 0.03 ” 0.31 ” 1.583? ”

17 0.04 ” 0.31 ” 1.512 ”

18 0.01 ” 0.32 ” 1.466 ”

19 0.00 ” 0.18 ” 1.412 ”

20 0.01 ” 0.36 ” 1.411 ”

21 0.06 ” 0.22 ” 1.402 ”

22 0.00 ” 0.30 ” 1.495* ”

23 2 0.08 3 1.469 3

[5]Fifty minute determinations

24 0.04 1 0.06 2 1.564 2

25 0.04 ” 0.11 ” 1.491 ”

26 0.05 ” ? ” 1.512 ”

27 0.03 ” 0.05 ” 1.532 ”

[6]Fifteen minute determinations

28 0.05 1 0.08 2 1.340 2

29 0.04 ” 0.05 ” 1.325 ”

30 0.06 ” 0.05 ” 1.335 ”

31 0.00 ” 0.00 ” 1.347 ”

32 0.03 ” 0.03 ” 1.412 ”

33 0.02 2 0.02 3 1.363 3

34 0.02 ” 0.06 ” 1.377 ”

35 0.00 ” 0.02 ” 1.363 ”

[5] This marked the time when the oxides first settled, leaving a

colorless supernatant liquid.

[6] This marked the time when the solution was first decolorized.

Inspection of the table will show that whether the oxygen were

determined immediately after the subsidence of the oxides (i.e.

after fifty minutes) or after three hours the results obtained are

practically the same. The tendency of the potassium permanganate to

lose strength made the frequent preparation of new samples advisable.

Wherever a new sample has been used in the course of the experiments,

the fact has been noted in the table by an asterisk. It will be noticed

that where a new solution is used the figures for flask no. III are

immediately larger and nearer to one and one half atoms of oxygen

from each molecule of potassium permanganate.

A phosphorus gas-pipette was used for the absorption of the oxygen in

all the experiments the results of which are embodied in the foregoing

table. In subsequent experiments an alkaline solution of pyrogallol was

employed. It is now known that the variation in the composition of the

manganese oxide in use had some influence upon the results.

It has also been found that the manganese dioxide prepared by the

reduction of permanganate by manganese sulphate is much less stable

than was supposed at the time this work was begun. The dioxide

prepared in this way begins immediately to lose oxygen spontaneously

but recovers the same in the presence of an excess of potassium

permanganate. In the light of these facts it is easy to understand

why lower results were obtained when the oxygen was determined

immediately after the disappearance of the color of the permanganate

and before the suspended oxide had subsided. It appears that the

manganese oxide employed in these experiments was not, as was supposed

at the time, the dioxide but one containing a smaller proportion of

oxygen. If such is the case the first action of the permanganate upon

it would be to replace the oxygen which had been lost. The reduction of

the remaining permanganate would then probably be in accordance with

the equation,

The reaction between manganese dioxide and potassium permanganate · 第 9 / 29 题