T = E²/(4R × 9.81)

It will be seen that an element thus charged gives as much energy as

5.3 large Bunsen elements.

The battery is charged with 10 liters of solution, and is capable of

furnishing for 5 hours a current of 7 amperes with a difference of

potential of 9 volts at the pile terminals. The work, according to the

formula (EI)/g, equals 6.422 kilogram-meters; with a feebler

resistance in the external circuit it is capable of producing a

current of 19 amperes for an hour and an half. In this case the

resistance of the external circuit equals the interior resistance of

the pile. Upon immersing the electrodes in new liquid, and with no

resistance in the external circuit, the current may reach 100 amperes.

On renewing the liquids during the operation of the pile, a current of

7 amperes is kept up if about a liter of saturation per hour be

allowed to pass into the battery. For five hours, then, only 5 liters

are used instead of the 10 that are necessary when the liquid is not

renewed while the pile is in action.--_La Nature._

* * * * *

Scientific American Supplement, No. 443, June 28, 1884 · 第 29 / 47 题