This, after integration, gives

/ 5 5 \ / 21 \

M/b = ( 1 + n + -n squared + -n cubed) [alpha]0 - ( 3n + 3n squared + --n cubed) [alpha]1

\ 4 4 / \ 8 /

/15 15 \ /35 \

+ ( --n squared + --n cubed) [alpha]2 - ( --n cubed ) [alpha]3,

\ 8 8 / \24 /

where

[alpha]0 = [phi]2 - [phi]1

[alpha]1 = sin ([phi]2 - [phi]1) cos ([phi]2 + [phi]1)

[alpha]2 = sin 2([phi]2 - [phi]1) cos 2([phi]2 + [phi]1)

[alpha]3 = sin 3([phi]2 - [phi]1) cos 3([phi]2 + [phi]1).

The part of M which depends on n cubed is very small; in fact, if we

calculate it for one of the longest arcs measured, the Russian arc, it

amounts to only an inch and a half, therefore we omit this term, and put

for M/b the value

/ 5 \ /15 \

(l + n + --n squared) [alpha]0 - (3n + 3n squared) [alpha]1 + ( --n squared) [alpha]2.

\ 4 / \ 8 /

Now, if we suppose the observed latitudes to be affected with errors,

and that the true latitudes are [phi]1 + x1, [phi]2 + x2; and if further

we suppose that n1 + dn is the true value of a - b:a + b, and that n1

itself is merely a very approximate numerical value, we get, on making

these substitutions and neglecting the influence of the corrections x on

the _position_ of the arc in latitude, i.e. on [phi]1 + [phi]2,

/ 5 \ / \ /15 \

M/b = ( 1 + n + --n1 squared)[alpha]0 - (3n1 + 3n1 squared)[alpha]1 + ( --n1 squared)[alpha]2

\ 4 / \ / \8 /

_ _

| / 5 \ / \ /15 \ |

+ | ( 1 + -- n1 )a0 - ( 3 + 6n1 )a1 + ( -- n1 )a2 | dn

|_ \ 2 / \ / \4 / _|

_ _

| da1 |

+ | 1 + n1 - 3n --- | da0;

|_ da0_|

here da0 = x2 - x1; and as b is only known approximately, put b = b1(1 +

u); then we get, after dividing through by the coefficient of da0, which

is = 1 + n1 - 3n1 cos([phi]2 - [phi]1) cos([phi]2 + [phi]1), an equation

of the form x2 = x1 + h + fu + gv, where for convenience we put v for

dn.

Now in every measured arc there are not only the extreme stations

determined in latitude, but also a number of intermediate stations so

that if there be i + 1 stations there will be i equations

x2 = x1 + f1u + g1v + h1

x3 = x1 + f2u + g2v + h2

: : :

: : :

x_i = x1 + f_iu + g_iv + h_i

In combining a number of different arcs of meridian, with the view of

determining the figure of the earth, each arc will supply a number of

equations in u and v and the corrections to its observed latitudes.

Then, according to the method of least squares, those values of u and v

are the most probable which render the sum of the squares of _all_ the

errors x a minimum. The corrections x which are here applied arise not

from errors of observation only. The mere uncertainty of a latitude, as

determined with modern instruments, does not exceed a very small

fraction of a second as far as errors of observation go, but no accuracy

in observing will remove the error that may arise from local attraction.

This, as we have seen, may amount to some seconds, so that the

corrections x to the observed latitudes are attributable to local

attraction. Archdeacon Pratt objected to this mode of applying least

squares first used by Bessel; but Bessel was right, and the objection is

groundless. Bessel found, in 1841, from ten meridian arcs with a total

amplitude of 50 deg..6:

a = 3272077 toises = 6377397 metres.

e (ellipticity) = (a - b)/a = 1/299.15 (prob. error +- 3.2).

The probable error in the length of the earth's quadrant is +- 336 m.

We now give a series of some meridian-arcs measurements, which were

utilized in 1866 by A.R. Clarke in the _Comparisons of the Standards of

Length_, pp. 280-287; details of the calculations are given by the same

author in his _Geodesy_ (1880), pp. 311 et seq.

Encyclopaedia Britannica, 11th Edition, "Dyer, Sir Edward" to "Echidna" Volume 8, Slice 9 · 第 70 / 84 题