By means of the formulae (18), which now reduce to

dP[Kappa] dP[Kappa] dP[Kappa]

[chi]` = ---------, [chi]`' = ----------, [chi]`" = ---------- ..., (25)

dP[kappa] dP[kappa]' dP[kappa]"

[Kappa] may also be expressed as a homogeneous quadratic function of

the cyclic velocities [.[chi]], [.[chi]]', [.[chi]]", ... Denoting it

in this form by [Tau]0, we have

[delta]([Tau]0 + [Kappa] = 2[delta][Kappa] = [delta]([kappa] [chi]` + [kappa]'[chi]`' + [kappa]"[chi]`" + ...). (26)

Performing the variations, and omitting the terms which cancel by (2)

and (25), we find

dP[Tau]0 dP[Kappa] dP[Tau]0 dP[Kappa]

-------- = - ---------, -------- = - ---------, ..., (27)

dPq1 dPq1 dPq2 dPq2

so that the formulae (23) become

dP[Tau]0 dP[Tau]0

Q1 = - --------, Q2 = - --------, ... (28)

dPq1 dPq2

A simple example is furnished by the top (MECHANICS, Sec. 22). The cyclic

co-ordinates being [psi], [phi], we find

( mu - [nu] cos [theta]) squared [nu] squared

2[@] = A[theta]` squared, 2[Kappa] = ----------------------- + -----,

A sin squared [theta] C

2[Tau]0 = A sin squared[theta][psi]` squared + C([phi]` + [psi] cos [theta]) squared, (29)

whence we may verify that dP[Tau]0/dP[theta] = - dP[Kappa]/dP[theta]

in accordance with (27). And the condition of equilibrium

dP[Kappa] dPV

--------- = - --------- (30)

dP[theta] dP[theta]

gives the condition of steady precession.

Encyclopaedia Britannica, 11th Edition, "Dyer, Sir Edward" to "Echidna" Volume 8, Slice 9 · 第 41 / 84 题