1. Action of Methyl Alcohol upon the Symmetrical chloride.

A portion of the chloride was dissolved in methyl alcohol, and the

solution boiled until a drop added to cold water gave no precipitate,

of unchanged chloride. The alcohol was then distilled off, and the

thick syrup remaining, diluted with water. This solution was

neutralized with barium carbonate and filtered. On cooling, the barium

salt crystallized in shining mica-like plates, or in yellowish needles

corresponding accurately with those described by Kastle. They gave the

following analytical results.

0.2664 gram lost 0.0211 gram at 150°, and gave 0.0870 gram BaSO₄.

[ COOCH₃ ]

[ / ]

Cal. for [C₆H₃——SO₂O ] Ba + 3H₂O

[ \ ]

[ NO₂ ]2

Found

H₂O = 7.79 7.88

[anhydrous salt] Ba = 20.85 20.85

2. In like manner the barium ethyl salt was made. It also agreed

perfectly with Kastle’s description, crystallizing in fine, colorless

needles, forming in tufts from a not too concentrated solution. In case

it is necessary to concentrate these solutions, it is of advantage

to add a small quantity of alcohol to the solution as this prevents

any great amount of saponification, which otherwise takes place to a

noticeable extent.

Analysis.

A Further Investigation of the Symmetrical Chloride of Paranitroorthosulphobenzoic Acid · 第 7 / 29 题