Set 1 on C to 57 on D; bring cursor to 57 on B (R.H., since 57 has an
_even_ number of digits); bring 1 on C to cursor, and under 7·3 on C
read 3140 on D. As a rough estimate we have √(57), about 8; 8 × 57,
about 400; 400 × 7, gives 2800, showing the result consists of 4
figures.
An expression of the form _a_∛(_b_^2), or _a_ _b_^⅔, is better dealt
with by rearranging as _a_ × (_b_)/(∛_b_).