COMBINED OPERATIONS.

Thus far the various operations have been separately considered, and we

now pass on to a consideration of the methods of working for solving the

various formulæ met with in technical calculations. We propose to

explain the methods of dealing with a few of the more generally used

expressions, as this will suffice to suggest the procedure in dealing

with other and more intricate calculations. In solving the following

problems, both the upper and lower scales are used, and the relative

value of the several scales must be observed throughout. Thus, in

solving such an expression as √((74·5)/(15·8)) = 6·86, the division is

first effected by setting 15·8 on B to 745 on A. From the relation of

the two parts of the upper scales (page 37) we know that such values as

7·45, 745, etc., will be taken on the _left-hand_ A and B scales, while

values as 15·8, 1580, etc., will be taken on the _right-hand_ A and B

scales. Hence, 15·8 on the R.H. B scale is set to 745 on the L.H. A

scale, and the result read on D under the index of C. Had both values

been taken on the L.H. A and B scales, or both on the R.H. A and B

scales, the results would have corresponded to _x_ = √((7·45)/(1·58)) =

2·17, or to _x_ =√((74·5)/(15·8)) = 2·17, _i.e_., to (6·86)/(√(10)).

Hence if a wrong choice of scales has been made, we can correct the

result by multiplying or dividing by √(10) as the case may require. If

the result is read on D, set to it the centre index (10) of B and read

the corrected result under the index of C.

To solve _a_ × _b_^2 = _x_. Set the index of C to _b_ on D, and over _a_

on B read _x_ on A.

To solve (_a_^2)/(_b_) = _x_. Set _b_ on B to _a_ on D by using the

cursor, and over index of B read _x_ on A.

To solve (_b_)/(_a_^2) = _x_. Set _a_ on C to _b_ on A, and over 1 on B

read _x_ on A.

To solve (_a_ × _b_^2)/(_c_) = _x_. Set _c_ on B to _b_ on D, and over

_a_ on B read _x_ on A.

To solve (_a_ × _b_)^2 = _x_. Set 1 on C to _a_ on D, and over _b_ on C

read _x_ on A.

To solve ((_a_)/(_b_))^2 = _x_. Set _b_ on C to _a_ on D, and over 1 on

C read _x_ on A.

To solve √(_a_ × _b_) = _x_. Set 1 on B to _a_ on A, and under _b_ on B

read _x_ on D.

To solve √((_a_)/(_b_)) = _x_. Set _b_ on B to _a_ on A, and under 1 on

C read _x_ on D.

To solve _a_ (_b_)/(_c_^2) = _x_. Set _b_ on C to _c_ on D and over _a_

on B read _x_ on A.

To solve _c_√((_a_)/(_b_)) = _x_. Set _b_ on B to _a_ on A, and under

_c_ on C read _x_ on D.

To solve (√_̅a_)/(_b_) = _x_. Set _b_ on C to _a_ on A, and under 1 on C

read _x_ on D.

To solve (_a_)/(√_̅b_) = _x_. Set _b_ on B to _a_ on D, and under 1 on C

read _x_ on D.

To solve _b_√_̅a_ = _x_. Set 1 on C to _b_ on D, and under _a_ on B read

_x_ on D.

To solve √(_a_^3) = _x_. Treat as _a_√_̅a_.

To solve _a_√(_b_^3) = _x_. Treat as _a_√_̅b_ × _b_.

To solve (√_̅a_^3)/(_b_) = _x_. Treat as (√_̅a_ × _a_)/(_b_).

To solve √((_a_^3)/(_b_)) = _x_. Treat as (√_̅a_ × _a_)/(√_̅b_) =

√((_a_)/(_b_)) × _a_.

To solve √((_a_ × _b_)/(_c_)) = _x_. Set _c_ on B to _a_ on A, and under

_b_ on B read _x_ on D.

To solve (_a_ × _b_)/(√_̅c_) = _x_. Set _c_ on B to _b_ an D, and under

_a_ on C read _x_ on D.

To solve √((_a_^2 × _b_)/(_c_)) = _x_. Set _c_ on B to _a_ on D, and

under _b_ on B read _x_ on D.

To solve (_a_^2 × _b_^2)/(_c_) = _x_. Set _c_ on B to _a_ on D, and over

_b_ on C read _x_ on A.

To solve (_a_√_̅b_)/(_c_) = _x_. Set _c_ on C to _b_ on A, and under _a_

on C read _x_ on D.

To solve ((_a_ × √_̅b_)/(_c_))^2 = _x_. Set _c_ on C to _a_ on D,

and over _b_ on B read _x_ on A.

The slide rule · 第 57 / 138 题