We have

x

F(n + 1,x) - F(n,x) = - ------------------------------ F(n + 2,x),

([gamma] + n)([gamma] + n + 1)

whence we obtain

F(1,x) 1 x/[gamma]([gamma] + 1) x/([gamma] + 1)([gamma] + 2)

------ = -- ---------------------- ----------------------------

F(0,x) 1 + 1 + 1 + ...,

which may also be written

[gamma] x x

------- ----------- -----------

[gamma] + [gamma] + 1 + [gamma] + 2 + ...

By putting +- x squared/4 for x in F(0,x) and F(1,x), and putting at the same

time [gamma] = 1/2, we obtain

x x squared x squared x squared x x squared x squared x squared

tan x = -- -- -- -- tanh x = -- -- -- --

1 - 3 - 5 - 7 - ... 1 + 3 + 5 + 7 + ...

These results were given by Lambert, and used by him to prove that [pi]

and [pi] squared incommensurable, and also any commensurable power of e.

Encyclopaedia Britannica, 11th Edition, "Constantine Pavlovich" to "Convention" Volume 7, Slice 2 · 第 21 / 26 题