CHAPTER LXI

SYNCHRONOUS CONDENSERS

~Synchronous Condensers.~--A synchronous motor when sufficiently

excited will produce a leading current, that is, when over excited

it acts like a great condenser, and when thus operated on circuits

containing induction motors and similar apparatus for the purpose of

improving the power factor it is called a _synchronous condenser_.

Although the motor performs the duty of a condenser it possesses almost

none of the properties of a stationary condenser other than producing

a leading current, and is free from many of the inherent defects of a

stationary condenser.

The relation of power factor to the size and efficiency of prime

movers, generators, conductors, etc., and the value of synchronous

condensers for improving the power factor is generally recognized.

Induction motors and other inductive apparatus take a component of

current which lags behind the line pressure, and thereby lowers the

power factor of the system, while a non-inductive load, such as

incandescent lamps, takes only current in phase with the voltage and

operates at unity power factor.

Since transformers require the magnetizing current, they may seriously

affect the power factor when unloaded or partially loaded, but when

operating at full load their effect is practically negligible.

The relative effect of fully loaded and lightly loaded induction motors

on the power factor is indicated by the diagram, fig. 2,478. The

magnetizing current is nearly constant at all loads and is wattless,

lagging 90 degrees behind the impressed pressure, or at right angles to

the current which is utilized for power.

In the figure, AB is the magnetizing component, which is always

wattless, and CB the power component. The angle ACB gives the

phase relation between voltage and current; the cosine of this

angle CB ÷ AC is the power factor.

[Illustration: FIG. 2,478.--Diagram showing relative effect of fully

loaded and lightly loaded induction motors on power factor.]

It is evident from the diagram that if the load be reduced, the

side CB is shortened, and as AB is practically constant, the

angle of lag ACB is increased. It therefore follows that the

cosine of this angle, or the power factor is reduced.

The figure clearly shows the reason for the low power factor of

induction motors on fractional loads and also shows that since

the magnetizing current is practically constant in value, the

induction motor can never operate at unity power factor.

With no load, the side CB (real power) is just sufficient to

supply the friction and windage. If this be represented by DB,

since AB remains constant, the power factor is reduced to 10

or 15 per cent. and the motor takes from the line about 30 per

cent. of full load current. It therefore follows that a group

of lightly loaded induction motors can take from the system a

large current at exceedingly low power factor.

The synchronous motor when used as a condenser, as before stated,

has the property of altering the phase relation between pressure and

current, the direction and extent of the displacement being dependent

on the field excitation of the condenser.

It can be run at unity power factor and minimum current input, or

it can be over excited and thereby deliver leading current which

compensates for the inductive load on other parts of the system. The

synchronous condenser, therefore, can supply magnetizing current to

the load on a system while the power component is supplied by the

generators.

[Illustration: FIG. 2,479.--General Electric 400 kw., 550 volt, 600

R.P.M., ~synchronous condenser~ with direct connected exciter installed

in sub-station No. 1 of the Colorado Light & Power Co., Cripple Creek,

Colo. The machine is designed for alternating current starting by means

of a compensator. The field is provided with a standard synchronous

motor winding, and, in addition, an amortisseur winding which assists

in starting and serves as a damping device to minimize hunting.]

[Illustration: FIG. 2,480.--Diagram showing relative location of

alternators and synchronous motors in plant of Witherbee Sherman & Co.,

Mineville N. Y. The distribution system of the Company is provided

with three synchronous motors, as shown. The system includes two

hydro-electric, one turbine driven, and one engine driven generator

plants; from three of these, current is transmitted to the fourth,

which is located in Mineville, at the point "A", the current being

distributed to the motor circuits from the points "A" and "B." The

transmission to the central station at Mineville is over three phase

circuits at 6,600 volts. For operating the mine at Cheever, current

is transmitted direct from the generating station at Port Henry. The

distribution from "A" and "B" is all at 3,300 volts, being stepped down

to 440 volts for the operation of the motors, which have a total rated

capacity of 4,762 horse power. Excepting three synchronous motors,

the load is practically all inductive, there being less than 10 kw.

required for lighting. The actual power demand ranges from 60 to 65

per cent. of the rated motor capacity, and prior to the installation

of the synchronous motors, the power factor was approximately 68 per

cent., the condenser effect of these motors making it possible to

maintain an average of about 90 per cent. power factor in spite of

the fact that a considerable portion of the induction motor load is

very widely distributed. The three synchronous motors are partially

loaded, each motor driving an air compressor through belting. The 180

kva. motor at Cheever takes about 150 kw. for the operation of a 1,250

cubic foot compressor, while the two 360 kva. machines take about 300

kw. each, for the operation of two 2,500 cu. ft. sets. The operation

of these compressors affords a method of utilizing a portion of the

motor capacity mechanically, inasmuch as the load on the motors is

practically constant during the time the mines are in operation, and

thereby permit the motors to be run at approximately 80 per cent. power

factor.]

~Effects of Low Lagging Power Factors.~--Transformers are rated in kva.

output; that is, a 100 kva. transformer is supposed to deliver 100 kw.

at unity power factor at normal voltage and at normal temperatures;

but, if the power factor should be, say .6 lagging, the rated energy

output of the transformer would be only 60 kw. and yet the current

and, consequently, the heating would be approximately the same as when

delivering 100 kw. at unity power factor.

[Illustration: FIG. 2,481.--Field of a synchronous condenser. Note

the ~amortisseur winding~, _erroneously_ called ~_squirrel cage_~

~winding~, consisting of two end rings which serve to short circuit

spokes passing through the pole tips as shown. ~The amortisseur

winding~ _assists in_ ~starting~ _and serves also as a damping device

to minimize_ ~hunting~.]

The regulation of transformers is inherently good, being for small

lighting transformers about 1½ to 2 per cent. for a load of unity

power factor, and about 4 to 5 per cent. at .7 power factor. Larger

transformers with a regulation of 1 per cent. or better at a unity

power factor load, would have about 3 per cent. regulation at .7 power

factor.

Alternators also are rated in kva. output, usually at any value of

power factor between unity and .8.

The deleterious effects of low power factor loads on alternators

are even more marked than on transformers. These are, decreased kw.

capacity, the necessity for increased exciter capacity, decreased

efficiency, and impaired regulation.

Assume the case of a 100 kva. .6 power factor, 60 kw. output.

It is probable that normal voltage could be obtained only with

difficulty, unless the alternator was especially designed for

low power factor service. The lagging power factor current

in the armature sets up a flux which opposes the flux set up

by the fields, and in consequence tends to demagnetize them,

resulting in low armature voltage.

It is often impracticable, without the installation of new

exciters, to raise the alternator voltage by a further increase

of the exciting voltage and current. The field losses, and

therefore the field heating of the alternator, when it is

delivering rated voltage and current, are greater at lagging

power factor than at unity. Increased energy input and

decreased energy output both cause a reduction in efficiency.

[Illustration: FIG. 2,482.--Diagram of a section of the Northern

California Power Co.'s transmission system, showing relative location

of alternators and synchronous condenser. The synchronous condenser is

installed at Kennett, which is served by generating stations at Kilarc

and Volta, located respectively 28 and 38 miles from the point at which

the condenser is operated. The local demand amounts to about 6,500

kw., and before the installation of the synchronous condenser, the

power factor was about 79 per cent. and after installing, about 96 per

cent. while the voltage at the point where the synchronous condenser

is installed is raised approximately 10 per cent. during the change

from no load to full load. In order to obtain close voltage regulation,

a regulator is used in connection with the synchronous condenser

and holds the voltage, at the center of distribution, within 2 per

cent. The regulator is mounted on the side of the control panel and

connected in the field of the synchronous condenser to automatically

change the excitation and compensate for voltage variations. A graphic

demonstration of the improvement in voltage regulation, which has been

secured in this case, is given by the curve drawing voltmeter records

reproduced in fig. 2,483.]

The regulation at unity power factor of modern alternators capable of

carrying 25 per cent. overload, is usually about 8 per cent. Their

regulation at .7 power factor lagging is about 25 per cent. The effect

of low power factor on the lines can best be shown by the following

example:

EXAMPLE.--Assuming a distance of five miles and a load of 1,000

kw. and desiring to deliver this load at a pressure of about

6,000 volts, three phase, with an energy loss of 10 per cent.,

each conductor at unity power factor would have to be 79,200

c.m., at .9 power factor, 97,533 c.m., and at .6 power factor,

218,000 c.m. In other words, at the lower power factor of .6,

the investment in copper alone would be 2.8 times as much.

[Illustration: FIG. 2,483.--Curve drawing ~voltmeter records~ at

Kennett, Cal. ~The upper curve~ shows voltage regulation with

synchronous condenser out of service, and ~the lower curve~, with

synchronous condenser in operation.]

If the same size of wire were used at both unity and .6 power

factor lagging, the energy loss would be about 2.8 times

the loss at unity power factor, or about 28 per cent. Low

lagging power factor on a system, therefore, will generally

mean limited output of prime movers; greatly reduced kilowatt

capacity of generator, transformer and line; and increased

energy losses. The regulation of the entire system will also be

poor.

~Cost of Synchronous Condenser vs. Cost of Copper.~--Referring to the

example given in the preceding paragraph, and calculating the necessary

extra investment in copper with the .6 power factor load, and copper

at 17 cents per pound, the result is that 29,292 pounds more copper is

required than with the power factor of .9 which means a total extra

investment in copper alone of $5,000 (29,292 × $.17). A synchronous

condenser of sufficient capacity to accomplish the same result would

cost about the same amount. It would therefore cost less to install the

condenser because at the same time a considerably increased capacity

would be obtained from the alternators, transformers, etc.

[Illustration: FIG. 2,484.--Diagram showing the ~field current taken

by a synchronous motor~ of normal design when operating at normal kva.

input at various power factors. ~It will be noted~ that a ~slight

departure from unity power factor necessitates a considerable change

in field current~. As the field curves increase with the square of the

current, there is a rapid increase in temperature with leading current.

_This action of leading or lagging current serves automatically to keep

the flux constant in the armature with changes in field excitation._

~When the motor is running at unity power factor~, an increase in field

excitation causes a leading current to flow, and at the same time

this leading current demagnetizes the field until the density of the

armature is restored to its normal value. ~If the field be decreased~

a lagging current flows which in turn magnetizes the field bringing

the density back to its original value. Therefore, with a constant

line voltage, the iron losses in a synchronous motor are approximately

constant irrespective of the field excitations with the exception that

the internal voltage will vary slightly due to the armature I R drop,

the density being a trifle lower at full load than at no load.]

~Synchronous Condenser Calculations.~--In figuring on the installation

of a condenser for correcting power factor troubles, a careful survey

of the conditions should be made with a view of determining just what

these troubles are and to what extent they can be remedied by the

presence of a leading current in the system.

[Illustration: FIG. 2,485.--Diagram showing a set of ~phase

characteristic curves~ taken ~from~ a General Electric _synchronous

motor_. ~These curves show~ _the current input to the motor at various

loads with constant voltage and varying field excitation_. There is a

certain field current at each load that causes a minimum current. Any

increase or decrease of field from the value increases the current and

causes it to lead or lag with respect to the line voltage. By referring

to the _minimum input_ curve, it will be noted that if the machine

be running at full load minimum input current and load is taken off,

the current will be leading or vice versa. In each case the phase

characteristic curve was run back on the lagging side to the break down

point. ~At no load~ and one quarter load the motor still ran in step

when the field was reduced to zero and even taken off altogether, and

it was necessary to reverse the field current in order to back down

the motor. ~The motor runs without slip~, as a synchronous motor, in

this condition, obtaining its excitation from the lagging current and

running as a reaction machine. The amount of load a machine will carry

without field varies with the design, the average being about 40% of

full load. ~It will be noted~ from the _limit of stability_ curve that

the lighter the load on the machine when it breaks down from lack of

sufficient excitation, the greater the current input at this point.

~The no load characteristic~ rises sharply on each side with slight

change in field current, while it flattens out with increase in load

until at overload the current input is practically the same throughout

a large range of field current.]

[Illustration: FIG. 2,486.--Comparison of the ~speed current curves~

and ~speed power factor curves~ of a typical synchronous, and induction

motor. It will be noted that the power factor of the synchronous motor

at start is higher than that of the induction motor owing to the higher

resistance of the squirrel cage winding. ~As the machine approaches

synchronism~, however, the magnetizing current of the induction motor

drops to a very much lower value than in the synchronous motor and

the power factor is consequently much higher. The magnetizing current

of the induction motor at full speed is usually 25 per cent. of full

load current while that of the synchronous motor is from 200 to 250

per cent. of full current, or even higher when running full speed

and normal voltage. This of course is due to the large air gap on

the synchronous machine. ~The current at start~ with full voltage

applied is usually higher in an induction motor owing to the fact

that the total impedance of the stator and rotor are less due to the

greater distribution of the windings and the lower resistance of the

squirrel cage. ~The high magnetizing current~ of a synchronous motor

should not be lost sight of as it is a very important consideration

in starting the machine. Even though the motor can be brought

practically to synchronous speed while still on the compensator, if

line voltage be thrown on, there will be a very heavy rush of current.

The obvious thing to do is to get the field on the motor while still

on the compensator, whenever possible, to avoid the high magnetizing

current. This magnetizing current is obviously equal to the circuit

current of the machine at no load field. In some cases additional

torque near synchronism can be obtained by short circuiting the field

winding through the field rheostat. This has the effect of reducing

the resistance of the rotor winding to some extent and causing the

motor to have less slip with a given load. The gain from this source

is small, however, in most cases, as the self-inductance of the field

winding is so high as to allow very little current to flow even if the

field be short circuited so that the total effective resistance of the

rotor winding is not materially reduced. In some cases where the torque

is nearly sufficient, however, enough gain may be obtained to take

care of the conditions. ~If the field be short circuited~ before the

motor is started there will be a reduction in starting torque and an

increase in current from the line, hence if this method be resorted to,

arrangements must be made to short circuit the field after the motor

has come to constant speed.]

It is necessary to possess a thorough knowledge of the system, covering

the generating capacity in energy and kva., average and maximum load,

and power factor on the alternators, average and maximum load, and

power factor on the feeders, system of distribution, etc.

[Illustration: FIG. 2,487.--Curves showing amount of wattless component

required to raise the power factor of a given kw. load to required

higher value. The wattless components are expressed as percentages of

the original kw. load. ~The numbers at the right~ which indicate the

points of tangency of the power factor curves to the 100 per cent.

line, show the amount of wattless component required to raise a given

kw. load of given lagging power factor to unity power factor. Obviously

the addition of further wattless component in a given case would result

in a leading power factor less than unity.]

The desirable location of a condenser is, of course, nearest the

inductive load in order to avoid the transmission of the wattless

current, but it often happens that a system is so interconnected that

one large condenser cannot economically meet the conditions, in which

case it may be better to install two or more smaller ones.

The question of suitable attendance should also be considered and, for

this reason, it may be necessary to compromise on the location. When

the location of the condenser has been decided upon and the load and

power factor within its zone determined, the proper size of condenser

to raise the power factor to a given value can be found as follows:

The method of procedure can best be explained by reference to

a concrete case. Assume a load of 450 kw. at .65 power factor.

It is desired to raise the power factor to .9. What will be the

rating of the condenser?

[Illustration: FIG. 2,488.--Diagram for synchronous condenser

calculations.]

Referring to the diagram, fig. 2,488, it is necessary to start

with 450 kw. At .65 power factor, or 692 kva., this has a

wattless lagging component of √(692² - 450²) = 525 kva. With

the load unchanged and the power factor raised to .9, there

will be 500 apparent kva., which will have a wattless component

of √(500² - 450²) = 218 kva.

It is obvious that the condenser must supply the difference

between 525 kva. and 218 kva., or 307 kva. A 300 kva. condenser

would, therefore, meet the requirements.

If it be desired to drive some energy load with the condenser

and still bring the total power factor to .9, proceed as

indicated in fig. 2,489. Assume a total load of 150 kw. on the

motor. As before, 450 kw. at .65 power factor, or 692 kva.,

with a wattless component of 525 kva.

The energy load will be increased from 450 to 600 kw. as

indicated, and with the power factor raised to .9 there will be

a kva. of 667 with a wattless component of √(667² - 600²) = 291.

There must be supplied 525 - 291 = 234 in leading kva.

The synchronous motor then must supply 150 kw. energy

and 234 kva. wattless, which would give it a rating of

√(150² + 234²) = 278 kva. at .68 power factor.

[Illustration: FIG. 2,489.--Diagram for synchronous condenser

calculation for cases where it is desired to drive some energy load

with the condenser and still bring the total power factor to .9.]

The standard 300 kva. condenser would evidently raise the power

factor slightly above .9 power factor leading.

By reference to the chart, fig. 2,490, the size of the required

condenser can be obtained direct without the use of the above

calculation. The method of using this curve is as follows:

Assume a load of say 3,000 kw. at .7 power factor and that it

be desired to raise the power factor to .9. Run up the vertical

line at 3,000 kw. to the .7 power factor line, and from there

along the horizontal line to the margin and find a wattless

component at this power factor of 3,000 kva., approximately.

Again run up the 3,000 kw. vertical line to the .9 power factor

line and from there along the horizontal line to the margin

and find a wattless component of 1,500 kva. The rating of the

condenser will then be 3,000 kva. - 1,500 kva. = 1,500 kva.

This table of course can be used for hundreds of kilowatts as

well.

[Illustration: FIG. 2,490.--Curve showing the relation of energy load

to apparent load and wattless components at different power factors.]

For determining the rating of a synchronous motor to drive an

energy load this curve is not so valuable, although it can

be used in determining the wattless component direct in all

cases where the energy component and power factor are known.

Knowing this energy component and power factor or wattless

component, the energy load can obviously be found by referring

to the curved lines on the diagrams, the curve that crosses the

junction of the vertical energy line and the power factor or

wattless component line giving the total apparent kva.

Hawkins Electrical Guide v. 07 (of 10) Questions, Answers, & Illustrations, A progressive course of study for engineers, electricians, students and those desiring to acquire a working knowledge of electricity and its applications · 第 7 / 8 章